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	@fanking
ThE cubic polynomial f(x) is such that the coefficient of x3 is -1 and the roots of the equation f(x) = 0 are 1, 2 and k. given that f(x) has a remainder of 8 when divided by x - 3, find. i)the value of k, posted: 22 May 10 / last action: July 2010
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	@akushika	12 July 10
	f(x)=(x-1)(x-2)(x-k)_f(x)=x3-3x2+2x-kx2+3xk-2k_f(x)=x3-3x2-2x-2k_f(x)=x3-[3+k]x2+2x-2k_divisor=x-3=0_x=3_f(x)=333-(3-k)33+23-2k_f(3)=27-27-9k-6-2k=8_-11k-6=8_k=-14/11